jayantakumarhotta67 jayantakumarhotta67 Answer: option three is not a … Start studying Copper lab observations and equations. x(2*am Cu/2*mm CuO) + y(4*am Cu/2*mm) = 0.88 Cu2O Solve the two equations simultaneously for x and y. x gives you grams CuO. 17. In many cases a … In the second step of Reaction I, a. the reaction mixture is diluted with HCl to form CuCl2 b. the reaction mixture is diluted with additional HNO3 to form Cu(NO3)2 c. the reaction mixture is diluted with water to form hexaaquocopper (II) ions d. all of the above are correct 10. In which of the following chemical equations, the abbreviations represent the correct states of the reactants and products involved at reaction temperature? This converts Cu from CuO and Cu from Cu2O to grams Cu that you end up with of 0.88 g. mm stands fr molar mass. If you use 2 HCl(aq), or 2 H^+(aq) + 2 Cl^-, the Cl^- ions would be left out to give the net ionic equation. Step 7: CuO(s) + H2SO4(aq)­ -> CuSO4 + H2O(l) – Double Replacement Step 9: Zn(S) + H2SO4(aq) -> ZnSO4(aq) + H2(aq) – Single Replacement 3. The reaction of excess zinc with sulfuric acid is a critical step in this investigation. The same would be true if the acid was nitric or sulfuric. Add your answer and earn points. Fe203 +3Co->2Fe +3C02 iii., 2K+F2=2KF ív. BaCl, +H2SO4→BASO4->2HCI 1 See answer Adityakonamwar is waiting for your help. When copper is heated in the presence of air at high-temperature copper (Cu) goes under an oxidation reaction to give out a black color substance that is a copper oxide (CuO). Solved: Identify the oxidizing and reducing agents in the equation. Learn vocabulary, terms, and more with flashcards, games, and other study tools. CuO+H2 → Cu +H20 11. [Cu(H2O)6]2+ ions are oxidized to copper (II) oxide (CuO) 9. Click here👆to get an answer to your question ️ Identify the oxidising agent (oxidant) in the following reactions. It easily transforms into copper oxide CuO more stable, either in the solid state by a thermal dehydration or at room temperature, in aqueous basic solutions. Determine what is oxidized and what is reduced. It is obtained in lab by dissolving CuO, Cu(OH) 2 or CuCO 3 in dil H 2 SO 4.The solution on crystallization gives blue triclinic crystals of CuSO 4 5H 2 O.. CuO + H 2 SO 4 → CuSO 4 + H2O Cu(OH) 2 + H 2 SO 4 → CuSO 4 + H 2 O CuO + H2→ Cu + H2O `CuO(s) + H_2(g) -> Cu(s) + H2O(l)` In this reaction, copper (II) oxide reacts with hydrogen to generate copper metal and water. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but PhC2H5 + O2 = PhOH + CO2 + H2O will; Compound states [like (s) (aq) or (g)] are not required. am stands for atomic mass. If you do not know what products are enter reagents only and click 'Balance'. The general approach is to run a reaction; analyse the results; then write an equation accurately describing the results. 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